I am using Lucid Lynx with Skype 2.1 in my PATH environment variable.
How to confirm this bug:
Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56)
[GCC 4.4.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import Skype4Py
>>> s = Skype4Py.Skype()
>>> s.Client.Start()
>>> Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/pymodules/python2.6/Skype4Py/client.py", line 247, in Start
self._Skype._API.Start(Minimized, Nosplash)
File "/usr/lib/pymodules/python2.6/Skype4Py/API/posix_x11.py", line 360, in
Start
os.execlp('skype')
File "/usr/lib/python2.6/os.py", line 327, in execlp
execvp(file, args)
File "/usr/lib/python2.6/os.py", line 344, in execvp
_execvpe(file, args)
File "/usr/lib/python2.6/os.py", line 380, in _execvpe
func(fullname, *argrest)
ValueError: execv() arg 2 must not be empty
>>>
What should happen:
Skype shuold start.
How to fix this bug:
Change that line
os.execlp('skype')
to os.execlp('skype', '') or os.execlp('skype', argument)
in file: /usr/lib/pymodules/python2.6/Skype4Py/API/posix_x11.py
Packages installed:
ii python-skype 1.0.31.0-1 Skype API wrapper for Python
ii python 2.6.5-0ubuntu1
ii skype 2.1.0.81-1
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https://bugs.launchpad.net/bugs/566303
Title:
os.execlp takes two parameters
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