Hi, I'm trying to printf something when one timer generates an interrupt. u-boot version is 1.3.4. The steps I've followed: - #define CONFIG_USE_IRQ - I've enabled interrupts - I've enabled timer interrupt - I've enabled timer - I've checked interrupt masks - I've checked interrupt status flags prior to timer interrupt The problem is that when timer generates interrupt (reaches 0 after several cycles), I expect default u-boot code "do_irq", called from ".irq:" address defined in "start.S" get executed. In that function is where I want to printf anything to check it is working. But the whole system hangs. When timer generates the interrupt, ARM9 hangs without printing anything and normal execution is freezed. printf and serial driver work perfectly because I've checked the steps above with prinft debugguing. I bet that when timer interrupts CPU, it jumps to code section not defined. The question is... How can I program the expected behaviour? I mean executing "do_irq" when the interrupt is generated. Thanks in advance for your help. Best regards, Ricardo Martinez
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