Dear ba_f,
In message <5c515fb3b2f956768d10d2e2c2e94...@rbg.informatik.tu-darmstadt.de>
you wrote:
>
> But the kernel crushes pretty early with the following u-boot output:
>
> ## Starting application at 0x01000000 ...
> ## Application terminated, rc = 0x1
This is NOT a crash. The program terminates normally with a return
code of 1.
> What may cause "Application terminated, rc = 0x1"?
Something that takes the same effect as "return(1)" from your main()
function, resp. an "exit(1)" from other parts of the code.
> I don't think it is a regular code exit, like main(){ return 1; }.
But yes, it is. From the line
## Application terminated, rc = 0x1
you can see that the program returned normally to U-Boot, and U-Boot
continues running (unless your code destroyed any of the U-Boot
execution environment).
Best regards,
Wolfgang Denk
--
DENX Software Engineering GmbH, Managing Director: Wolfgang Denk
HRB 165235 Munich, Office: Kirchenstr.5, D-82194 Groebenzell, Germany
Phone: (+49)-8142-66989-10 Fax: (+49)-8142-66989-80 Email: w...@denx.de
I express preference for a chronological sequence of events which
precludes a violence. - Terry Pratchett, _The Dark Side of the Sun_
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