The following URLs won't parse using the "tweet" button: "'url' parameter does not contain a valid URL."
http://www.pitchero.com/clubs/stockport/j/team-news-1249.html&news_id=247910 I expect this is because the string has an ampersand "&" rather than a question mark "?" before the first GET variable. Facebooks "share" and "like" functions both accept this formatting, as do Google and Yahoo. Is there a reason Twitter's API does not? Is there any work around I can use? Thanks -- Twitter developer documentation and resources: http://dev.twitter.com/doc API updates via Twitter: http://twitter.com/twitterapi Issues/Enhancements Tracker: http://code.google.com/p/twitter-api/issues/list Change your membership to this group: http://groups.google.com/group/twitter-development-talk
