Hello All,
You can find a sample HTTP POST request using HTTP multipart/form-data
at the end of this message.
The server that handles this request is using twisted so I end up with a
Request object. Is there a way I can extract the file name
("image008.jpg") from this stream? I'm looking at the source of
cgi.parse_multipart() and it seems to be ignored.
Best regards Burak
PS:
POST /put HTTP/1.1
Host: localhost:7111
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:48.0) Gecko/20100101 Firefox/48.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Connection: keep-alive
Content-Type: multipart/form-data;
boundary=---------------------------352471062160373366296932264
Content-Length: 382691
-----------------------------352471062160373366296932264
Content-Disposition: form-data; name="name"
a
-----------------------------352471062160373366296932264
Content-Disposition: form-data; name="version"
1
-----------------------------352471062160373366296932264
Content-Disposition: form-data; name="data"; filename="image008.jpg"
Content-Type: image/jpeg
(...)
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