On Jul 29, 2013, at 1:29 PM, Jorge Gonzalez <gjo...@google.com> wrote:
> Wouldn't it be possible that defer.gatherResults inserts its callback into d > before say slowFuncReturningDeferred_B gets to run and return its own > Deferred (and therefore chain it to what gatherRestults is ultimately waiting > for?). If so, wouldn't the results returned by slowFuncReturningDeferred_B > never make it to the results gathered by defer.gatherResults? No, that's not what happens. You call addCallback(lambda _: slowFunc...A()), then you call gatherResults. That means gatherResult's callback is after slowFuncReturningA() in d's callback chain. Can you attach an actual runnable code example with some behavior that you didn't expect, so we can actually run it and explain what's happening? No need for you to spin the reactor or anything, just instantiate a Deferred and then fire it. -glyph
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