Hi,
Using log.startLogging(open(logname, 'w'), setStdout=False)
very well solves the issue.. of stdout remaining untouched and log.msg()
calls going to log
Can we do this ?:
Log file gets -> both the log.msg() calls , the stdout +stderr
console -> gets stdout +stderr as usual
Regards
Naman
On Fri, Oct 30, 2009 at 9:25 PM, David Bolen <db3l....@gmail.com> wrote:
> naman jain <naman...@gmail.com> writes:
>
> > I wanted to log in a file and keep the console also going with it.
>
> I can read this as either:
>
> * Keep file logs and stdout/console completely separate, or
> * File gets explicit logs and copies of stdout, but stdout also goes to
> console as well.
>
> The latter is something I'd more commonly do, but the former is what
> you explain further below with your rules.
>
> > I am using
> > log.startLogging(open(logname, 'w'))
> >
> > whatever documentation I could find about this API, it suggested me to
> pass
> > setStdout=False(in order to keep stdout away from putting into log)
> > somewhere in the startlogging function.
> >
> > Something like this I tried:
> > log.startLogging(sys.stdout,setStdout=False)
>
> Why did you switch to sys.stdout here? While this will prevent
> sys.stdout and sys.stderr from being redirected, it will use
> sys.stdout for any log.msg() calls, so nothing would end up in your
> log file.
>
> > Doesnt help in solving the problem of getting both things:
> >
> > Requirement:
> > log.msg("messageforlog") -> goes to log
> > print "message for console" -> goes to console
> >
> > Could anyone give some ideas on this?
>
> I think you had the right idea with setStdout, but changed more than
> just that when you tested it. If you use a call like
> log.startLogging(open(logname, 'w'), setStdout=False) I believe you'll
> get what you want. Only calls to log.msg() will go to the file, and
> stdout/stderr will be left unchanged.
>
> -- David
>
>
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