Ralph Meijer wrote:
> On Tue, 2009-08-11 at 18:30 +0200, Gabriel Rossetti wrote:
>
>> [..]
>>
>
> Apparently you modified the original example here:
>
>
>> [..]
>> connector = XMPPClientConnector(reactor, "10.204.232.117", f)
>> connector.connect()
>>
>
> This would never work properly. XMPPClientConnector is designed to do an
> SRV record look up on the /domain/ provided as its second argument. You
> pass an IP address here and that will just fail.
>
> The original example passes client_jid.host. This extracts the domain
> from the JID you want to connect with and then follows the procedure of
> first trying to find xmpp-server SRV records for that domain, and if
> that fails, try to connect to the host that the domain name resolves to,
> using the default port (5222), as outlined in RFC 3920. Note that
> XMPPClientConnector avoids the problems sketched in ticket #3456 that
> was mentioned by Jean-Paul.
>
> If you really want to connect to a specific host instead of following
> the above procedure, you can do this instead of the code quoted above:
>
> reactor.connectTCP("10.204.232.117", 5222, f)
>
>
Hmmm, ok, it works on linux and windows though, but I did as you said
anyways as it's still flacky on mac. Thanks,
Gabriel
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