>>>>> "Doug" == Doug Farrell <dfarr...@mypublisher.com> writes:
Doug> Is there anything in LoopingCall to keep it from trying to run Doug> someFunction() if the previous call is still running? For instance a Doug> call to someFunction() takes longer than 5 seconds, will LoopingCall Doug> hold off or will it call someFuction() anyway causing two 'instances' Doug> to run? Hi Doug Sorry if it sounds like I'm being a PITA, but I really recommend reading the source code and writing & playing with a tiny example. Also see http://twistedmatrix.com/documents/8.2.0/api/twisted.internet.task.LoopingCall.html I suggest this because it's by far the best way to learn these things. And if you're using Twisted in any serious way, it's hard to get by without getting closely acquainted with some of the code. BTW, yes, LoopingCall will reschedule in a sensible way, supposing your task returns a deferred that takes a long time to fire :-) Try it. Terry _______________________________________________ Twisted-Python mailing list Twisted-Python@twistedmatrix.com http://twistedmatrix.com/cgi-bin/mailman/listinfo/twisted-python
