On 3/4/19 1:35 PM, David Rock wrote:
On Mar 4, 2019, at 15:28, john fabiani <jo...@jfcomputer.com> wrote:
I knew there was a simple why to get it done! But where is it off my a day?
comparing
$ cal
March 2019
Su Mo Tu We Th Fr Sa
1 2
3 4 5 6 7 8 9
10 11 12 13 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
31
to
import calendar as cal
cal.monthcalendar(2019,3)
[[0, 0, 0, 0, 1, 2, 3], [4, 5, 6, 7, 8, 9, 10], [11, 12, 13, 14, 15, 16,
17], [18, 19, 20, 21, 22, 23, 24], [25, 26, 27, 28, 29, 30, 31]]
I see the first element of the array is
[0, 0, 0, 0, 1, 2, 3]
where I would have expected
[0, 0, 0, 0, 0, 1, 2]
Which I’m sure is just a question of “defining the start of the week” properly,
but if you just took it as-is, Mar 1 would be Thursday, not Friday if you
translated literally.
—
David Rock
da...@graniteweb.com
My understanding is - a week starts on Monday and ends on Sunday. So
that looks correct. Below I use a max function but I wonder if I should
use a min function too. Recall I am looking for the string of the dates
for the week.
Here is my code:
import datetime
import calendar
#get the weeks of a month to get the dates to display
tday = datetime.datetime(2020,03,01)
weeksInMonth =calendar.monthcalendar(tday.year, tday.month)
lastdayof1stweek = weeksInMonth[0][6]
firstweek = tday.strftime("%m-%d_%Y")+ " - "+
datetime.datetime(tday.year, tday.month,
lastdayof1stweek).strftime("%m-%d-%Y")
print firstweek
for i in range(len(weeksInMonth)):
if i == 0:
continue
firstday = weeksInMonth[i][0]
lastday = max(weeksInMonth[i])
weekstr = datetime.datetime(tday.year, tday.month,
firstday).strftime("%m-%d-%Y") + ' - ' + datetime.datetime(tday.year,
tday.month, lastday).strftime("%m-%d-%Y")
print weekstr
def max(arr):
max_ = arr[0]
for item in arr:
if item > max_:
max_ = item
return max_
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