I think it could be solved in a much easier way.
s.replace('\n ', '')
In other words removing a new line followed by a space.
In such case, the approach is not by line.
f = open('file.ics')
content=f.read().replace('\n ', '')
f.close()
The real use case is an .ics file.
It works as expected but there's a thing I've to understand about the end of
line in general.
The original file line break is CR CF
cat --show-all file.ics
METHOD:PUBLISH^M$
BEGIN:VTIMEZONE^M$
I noticed that the end of file doesn't get preserve if I create a copy of the
file by simply
f = open('file.ics')
content=f.read()
f.close()
f = open('file_copy.ics', 'w')
write('content')
f.close()
cat --show-all file_copy.ics
METHOD:PUBLISH$
BEGIN:VTIMEZONE$
What am I missing?
----- Messaggio originale -----
Da: "Peter Otten" <__pete...@web.de>
A: "Tutor Python" <tutor@python.org>
Inviato: Lunedì, 4 febbraio 2019 20:23:59
Oggetto: Re: [Tutor] Remove soft line break
Valerio Pachera wrote:
>
> I have a file with row that split at the 80th character.
> The next row start with a blank space, meaning that i part of the previous
> row.
>
> Example:
>
> Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nam non justo
> enim. Viv
> amus dapibus quis neque vitae ornare. Pellentesque at pharetra sapien, id
> eleif end lacus. Nullam ut semper enim, vulputate venenatis justo.
> Vestibulum vehicul a dolor sit amet ultricies vulputate. Aenean lobortis,
> nulla eu scelerisque hen
>
> What do you suggest to get the text on a single line?
Neglecting the corner cases:
$ cat mergelines.py
def merge_lines(lines):
lines = (line.rstrip("\n") for line in lines)
accu = [next(lines)]
for line in lines:
if line.startswith(" "):
accu.append(line[1:])
else:
yield "".join(accu) + "\n"
accu = [line]
yield "".join(accu) + "\n"
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
