Hi All , I would like to know how do I make and option file as an argument on command propmnt in python .
At present I using : if len(sys.argv) == 3: first = sys.argv[1] second = sys.argv[2] else: print "enter the second argument" It works well for the following command : python test.py file1 file2 However I have another case where only file1 may be present so file1 is mandatory for this script to run however file2 is optionnal : if len(sys.argv) == 2: first_log = sys.argv[1] second_log = sys.argv[2] pthon test.py file1 It gives error : second_log = sys.argv[2] IndexError: list index out of range How do I acheive this because if python test.py file1 file2 then I would process both files . If python test.py file1 is given then I would process file1 using the variable first_log . Please advice . Thanks, _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor