On 29/11/2018 12:53, Asad wrote:
> Hi All ,
>
> I need some help to print error lines from a log file :
I don;t have time right now for a detailed analysis but
there are some obvious starting points:
> f4 = open (r"file1.log", 'r')
> string2=f4.readlines()
> for i in range(len(string2)):
Its usually easier to just use
for line in f4:
process line here...
> position=i
> lastposition =position+1
> while True:
> if re.search('ORA-20001: set_patch_metadata not
> called',string2[lastposition]):
You don;t need to use regular expressions for fixed strings.
A regular string search will be more efficient.
if searchString in line
> break
> elif lastposition==len(string2)-1:
If you uyse the for line in file idiom you don't need
this check. The loop will never run off the end.
> break
That break is not indented so will always exit the
loop on the first go round. I'll assume for now its just
a typo or email glitch...
> else:
> lastposition += 1
> errorcheck=string2[position:lastposition]
> print errorcheck
> I think the logic I am using is correct but need some expert comment to
> make it work also some guidance on how to print all the lines until the
> error is received .
The easiest way to do this is usually to set a flag True
when you hit the start line and then false when you hit
the end. print while the flag is True
for line in file:
if isStart(line): flag = True
if isEnd(line): flag = False
if flag: print line
Now write the isStart(line) and isEnd(line) functions and
you should be good to go.
Sorry if I'm missing something key, as I said I just
skimmed this.
gotta run,
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
http://www.flickr.com/photos/alangauldphotos
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