On 28/07/2015 18:00, ltc.hots...@gmail.com wrote:

Hi Everyone,

I'm trying to print a command of list options by using the help command in the 
iPython interpreter. Read captured copy of the printout as follows:

'Python 2.7.10 |Anaconda 2.3.0 (64-bit)| (default, May 28 2015, 16:44:52) [MSC 
v.
1500 64 bit (AMD64)]
Type "copyright", "credits" or "license" for more information.

IPython 3.2.0 -- An enhanced Interactive Python.
Anaconda is brought to you by Continuum Analytics.
Please check out: http://continuum.io/thanks and https://anaconda.org

In [1]: help list
   File "<ipython-input-1-823a3ff84bc4>", line 1
     help list
             ^
SyntaxError: invalid syntax.'


Question: What is the correct help command?


Standard iPython says this.

Python 3.4.3 (v3.4.3:9b73f1c3e601, Feb 24 2015, 22:44:40) [MSC v.1600 64 bit (AMD64)]
Type "copyright", "credits" or "license" for more information.

IPython 3.2.0 -- An enhanced Interactive Python.
?         -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help      -> Python's own help system.
object?   -> Details about 'object', use 'object??' for extra details.

In [1]: list?
Docstring:
list() -> new empty list
list(iterable) -> new list initialized from iterable's items
Type:      type

In [2]: list??
Docstring:
list() -> new empty list
list(iterable) -> new list initialized from iterable's items
Type:      type

In [3]: help(list)
Help on class list in module builtins:

class list(object)
 |  list() -> new empty list
 |  list(iterable) -> new list initialized from iterable's items
 |
 |  Methods defined here:
 |
 |  __add__(self, value, /)
 |      Return self+value.
...

Got it?

--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence

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