On 06/28/2014 02:20 PM, Albert-Jan Roskam wrote:
________________________________ From: Ken G. <beachkid...@gmail.com> To: tutor@python.org Sent: Saturday, June 28, 2014 7:59 PM Subject: [Tutor] Finding numeric day in a year...I know the correct answer should be 001, but I keep getting 179 which is the correct answer for June 28, 2014 (I think). I tried using datecode in various places instead of today but I am still getting 179. Currently using Ubuntu 12.04.4 and Python 2.7. Thanks for any feedback and suggestion. PROGRAM DISPLAY: # datefind 03.py import datetime datecode = "20140101" # from database on file month = datecode[4:6] day = datecode[6:8] year = datecode[0:4] datecode = year + "-" + month + "-" + day today = datecode print today print print "Day of year: ", datetime.date.today().strftime("%j") TERMINAL DISPLAY: 2014-01-01 Day of year: 179 ------------------ (program exited with code: 0) Press return to continueHello, Your variable 'today' and the datetime function 'today()' are not the same thing. You need strptime to parse the date string (and tell it the format is yyyymmdd), then strftime to format it using the day-of-year format '%j'datetime.datetime.strptime(datecode, "%Y%m%d").strftime("%j")'001'
Thanks! That did the trick. Thank you. Ken _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
