On 19/01/2014 13:23, spir wrote:
On 01/18/2014 07:20 PM, Pierre Dagenais wrote:
Hello,
I wish to fill a list called years[] with a hundred lists called
year1900[], year1901[], year1902[], ..., year1999[]. That is too much
typing of course. Any way of doing this in a loop? I've tried stuff like
("year" + str(1900)) = [0,0] but nothing works.
Any solution?
Thank you,
PierreD.
I think Danny & Wiktor's solutions are the right ones. Danny's is faster
a simpler (because of direct array indexing), but does not allow giving
the true year "names" (actually numbers). Wiktor more correctly matches
you expectation bt is a bit slower because we're searching individual
years in a dict.
I suspect that the speed difference between accessing a list by direct
indexing and looking up something in a dict is negligible. I'll happily
leave Steven D'Aprano to supply us with the actual figures from the
timeit module :)
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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