From: waynejwer...@gmail.com Date: Fri, 20 Aug 2010 15:07:56 -0500 Subject: Re: [Tutor] flow problem with a exercise To: rwob...@hotmail.com CC: tutor@python.org On Fri, Aug 20, 2010 at 2:48 PM, Roelof Wobben <rwob...@hotmail.com> wrote: Oke, I don''t understand it complety. return not arg%2 Why use not here ? I think that arg%2 is True not makes it false. What happens when you replace arg with a value? % is modulo division, so it just returns the remainder. 2 % 2 = ? 2%2=0 4 % 2 = ? 4%2=0 7 % 2 = ? 7%2=1 11 % 2 = ? 11%2 =1 What is the truth value of 0 and 1? print 'True' if 0 else 'False' False print 'True' if 1 else 'False' True So what is the outcome of the following? result = 2 % 2 print result, not result if not result: print 'Even' if result: print 'odd' 0 True Even So 1 is True and 0 is False according to Python. Another question. How can I round outcome of a calculation. round ( ( t-32)/1.8) does not work because I get a message that there are two arguments. Outcome = (t-32)/1.8 outcome2 = round (outcome) does not work because the argument must be a string or a number What is the type of t? In [39]: t = 3 In [40]: round((t-32)/1.8) Out[40]: -16.0 In [41]: t = 3.0 In [42]: round((t-32)/1.8) Out[42]: -16.0 Works fine for me. Correct, But I see one wierd thing. round ((42-32)/1.8) gives a output -16.0 but (42-32)/1.8) gives also -16.0 I was expectting that round will give 16 as output because round (32.0) is the same as round (32.0, 0) so there will be 0 decimals. And I see one decimal. Roelof HTH, Wayne
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