On Thu, Jun 11, 2009 at 11:58 AM, spir<denis.s...@free.fr> wrote: > Le Thu, 11 Jun 2009 10:46:26 -0400, > Kent Johnson <ken...@tds.net> s'exprima ainsi: > >> On Wed, Jun 10, 2009 at 9:43 PM, Robert Lummis<robert.lum...@gmail.com> >> wrote: >> > I want to write a function that I can use for debugging purposes that >> > prints the values of whatever list of object references it is given as >> > arguments, without knowing in advance how many object references it >> > will be called with or what they might be. For example, the call: >> > show(a,b,c) would output the values of the arguments like this: >> > >> > a = 3 >> > b = 'john' >> > c = 'Monday' >> > >> > while show (x) would output (for example): >> > >> > x = 3.14 >> >> Here is a pretty clean solution. It passes names rather than values, >> then looks the values up in the caller's stack frame. Written for >> Python 2.x but should work for 3.x if you change the prints. >> >> In [1]: import sys >> In [11]: def show(names): >> ....: frame = sys._getframe(1) >> ....: for name in names.split(): >> ....: if name in frame.f_locals: >> ....: print name, '=', frame.f_locals[name] >> ....: else: >> ....: print name, 'not found' >> > [...] >> >> Kent > > Waow, great! > > Denis > ------ > la vita e estrany > _______________________________________________ > Tutor maillist - tu...@python.org > http://mail.python.org/mailman/listinfo/tutor >
Thanks for all the intelligent and thoughtful replies to my newB question. It looks like this tutor mailing list is going to be a big help! It's going to take me some time and trial and error to digest all the replies so I understand them fully but it will be instructive. I guess one thing I learned already, even though I didn't ask about it, is that using python3 isn't the best way to start out. Again, thank you all for taking the time to reply. -- Robert Lummis _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
