Greetings, The book I have says when you anticipate that you will be working with numbers larger than what python can handle, you place an "L" after the number to signal python to treat it as a large number. Does this "treating" of the number only mean that Python won't try to represent the number internally as a 32bit integer? Python still appears to be representing the number only with an L behind it so what is happening to the number then. Is the L behind the number telling python to handle this large number in HEX instead which would fit into the 32 bit limit?
thanks in advance, John T _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
