> i create a list of all JPG files with:
> >>> list = glob.glob('*.JPG')
> the content of 'list' is now:
> >>> print list
> ['DSC00001.JPG', 'DSC00002.JPG', 'DSC00003.JPG']
>
> but what i want is this type of list:
> ['DSC00001', 'DSC00002', 'DSC00003']I would make use of os.path.splitext, which returns a tuple, where [0] is the path and filename, and [1] is the extension. In [1]: import os In [2]: mylist = ['DSC00001.JPG', 'DSC00002.JPG', 'DSC00003.JPG'] In [3]: newlist = list() In [4]: for x in mylist: ....: newlist.append(os.path.splitext(x)[0]) In [5]: newlist Out[6]: ['DSC00001', 'DSC00002', 'DSC00003'] Also, don't assign things to list, list() is a buildin function in Python, you don't want to say list = x, because then you can't get to the buitin list(). Brett _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
