Solution:
modes.sort(key=lambda item: int(item[1].split('x')[0])) # 2.4
modes.sort(lambda x, y: cmp(int(x[1].split('x')[0]),
int(y[1].split('x')[0]))) #2.3.5
Jonas Melian wrote:
> From an input as this:
>
>Standard timing 0: 85 Hz, 640x480
>Standard timing 1: 85 Hz, 800x600
>Standard timing 2: 85 Hz, 1024x768
>Standard timing 3: 85 Hz, 1280x1024
>Standard timing 4: 70 Hz, 1600x1200
>Standard timing 5: 60 Hz, 1920x1440
>
>I want to get columns 3 and 5 for sort them from mayor mo minor, so:
>
>85 1280x1024
>85 1024x768
>85 800x600
>85 640x480
>70 1600x1200
>60 1920x1440
>
>------
>modes = []
>i = 3; j = 5 # Columns for get
>for ln in data:
> if ln.startswith('Standard'):
> modes.append(ln.split()[i:j+1:j+1-i-1])
>
> >>> modes
>[['85', '640x480'], ['85', '800x600'], ['85', '1024x768'], ['85',
>'1280x1024'], ['70', '1600x1200'], ['60', '1920x1440']]
> >>> modes.sort()
> >>> modes
>[['60', '1920x1440'], ['70', '1600x1200'], ['85', '1024x768'], ['85',
>'1280x1024'], ['85', '640x480'], ['85', '800x600']]
>-------
>
>Well, it's from minor to mayor.
>But the big problem is that Python does lexicographic sorting on tuples.
>So, how sort the second column by the numbers before of 'x'?
>
>I'm supossing that there is to use split()
>
>Any help? please
>Thanks in advance!
>
>_______________________________________________
>Tutor maillist - Tutor@python.org
>http://mail.python.org/mailman/listinfo/tutor
>
>
>
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