Try: print X.readline() -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Servando Garcia Sent: Tuesday, May 10, 2005 2:37 PM To: Python help Subject: [Tutor] following the chain
Thanks to the many hints from the list I have made it to level four, of the python challenges. Many thanks to all. I truly have been looking for a solid example to follow on the use of the URL module. I don't feel am using it correctly or I am not understanding/using the clue correctly. Here is how I have been trying to use urlopen() import urllib name="some URL" X = urllib.urlopen(name) print X the output of X in very strange to me. I have include the exact output: <addinfourl at 585200 whose fp = <socket._fileobject object at 0x91068>> Have I used the urlopen() correctly? What is the meaning of the output? _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
