Dear group, For some reason my brain cannot think of any other
option than what I have in my script. Could any one
please help me in suggesting.
What I have : (File name : psl) 22 2 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 22 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0 24 1 457:411 25 0 22 0 457:411 25 0 21 0 457:411 25 0 25 0 457:411 25 0 25 0 457:411 25 0
What to do: I want to print values that are 25 in column 1 and not the other values such as 24,22,21 etc.
My script:
for i in range(len(psl)):
col = split(psl[i],'\t') col1 = col[0]
col1 is a text string, not a number, e.g. '25', not 25. The simplest thing is just to compare it to '25':
if col1 == 25:
if col1 == '25':
Kent
print col[0]+'\t'+col[1]+'\t'+col[17]
Result: I get nothing. Am I doing something very
wrong. Why isnt if col1 == 25: functional.
My idea is to check if col[0] == 25: then print
columns 1,18 etc.
Can you please help me.
Thanks K
__________________________________________________
Do You Yahoo!?
Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com _______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
_______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
