This code will work.
a=[1,0,0,0,0,1,1,1,0,1,1,0,1,0]
shorta=a[:]
while 0 in shorta:
shorta.reverse()
shorta.remove(0)
shorta.reverse()
print [0,]*(len(a)-len(shorta))+shorta
result=[0,]*(len(a)-len(shorta))+shorta
Juan Shen
在 2005年1月5日 星期三 11:44，Liam Clarke 写道：
> Sorry rephrase -
>
> So I have a list -
>
> [0,0,0,0,0,1,1,1,0,1,1,0,1,0]
>
> I want to move all the 1's move to the right, 1 index at a time,
> preserving any spacing.
>
> i.e.
>
> [1,0,0,0,0,1,1,1,0,1,1,0,1,0]
>
> [0,1,0,0,0,0,1,1,1,0,1,1,0,1]
>
> [0,0,1,0,0,0,0,1,1,1,0,1,1,1]
>
> [0,0,0,1,0,0,0,0,1,1,1,1,1,1]
>
> [0,0,0,0,1,0,0,0,1,1,1,1,1,1]
>
> [0,0,0,0,0,1,0,0,1,1,1,1,1,1]
>
> [0,0,0,0,0,0,1,0,1,1,1,1,1,1]
>
> [0,0,0,0,0,0,0,1,1,1,1,1,1,1]
>
>
> Now, I have a whole list of these lists.... and I create an array of them.
> Is there a way to apply these changes wholescale without a large
> calculation time?
>
> I'm starting to think I'm going to have to go Cpp for this kind of
> direct pixel tweaking stuff.
> (640x480 (let alone 1024x768) is a lot of pixels to run through a for...
> loop)
>
> So yeah, anyone had this before?
>
> Regards,
>
> Liam Clarke
>
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