Ok,

The structure has been ok already. I just missed to write the WEB-INF
dir in my mail.
I corrected my web.xml file in that way:
<?xml version="1.0" ?>

<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee";
xmlns:xsi="http://
www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/
j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd";>
    
<display-name>Testservlet</display-name>
... the rest is, as it was

I restarted Tomcat and tried again:
http://localhost:8080/XML_RPC_Testserveur

i even tried: 
http://localhost:8080/webapp/XML_RPC_Testserveur

I had no success.
The app I wrote is not to complex.
What did I miss?

Any Answers? 
Christian

On Fri, 1 Oct 2004 11:11:12 -0400, Shapira, Yoav <[EMAIL PROTECTED]> wrote:
> 
> Hi,
> Your web.xml is invalid: you can't have both 2.2 and 2.4 DTD/schema declarations.  
> Pick one, probably 2.4.
> 
> Your app structure is invalid.  Classes and libs go under [webapp]/WEB-INF, not just 
> [webapp].
> 
> Yoav Shapira
> Millennium Research Informatics
> 
> 
> 
> 
> >-----Original Message-----
> >From: Christian Ruediger [mailto:[EMAIL PROTECTED]
> >Sent: Friday, October 01, 2004 10:56 AM
> >To: Tomcat Users List
> >Subject: deploy simple HTTP doPost servlet to tomcat 5.0.28
> >
> >Hi folks,
> >after trying the complex aproach without any success, I started a
> >lowtech approach. I simply want a small servlet deployed. Can't be too
> >complicated.
> >
> >What I have:
> >Apache Tomcat 5.0.28 Server
> >Win 2000
> >j2sdk1.4.2_05
> >
> >I constructed the following structure in tomcats webapp folder:
> >
> >webapp -
> >   - classes
> >       - testserveur
> >           - XML_RPC_Servlet.class
> >   - libs
> >   - web.xml
> >
> >(dont bother the name XML_RPC_Servlet.its for future purposes.
> >currently only text is displayed -> see code below)
> >
> >web.xml is as follows:
> >
> ><!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//
> >DTD WebApplication 2.2//EN"
> >"http://java.sun.com/j2ee/dtds/web-app_2.2.dtd";>
> >
> ><web-app xmlns="http://java.sun.com/xml/ns/j2ee";
> >    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
> >    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
> >http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd";
> >    version="2.4">
> >
> ><display-name>Testservlet</display-name>
> ><context-parameter>
> ><param-name>Lieblingsfarbe</param-name>
> ><param-value>rot</param-value>
> ></context-parameter>
> >    <servlet>
> >      <servlet-name>XML_RPC_Testserveur</servlet-name>
> >      <servlet-class>
> >        testserveur.RPC_XML_Servlet
> >      </servlet-class>
> >    </servlet>
> >    <servlet-mapping>
> >      <servlet-name>XML_RPC_Testserveur</servlet-name>
> >      <url-pattern>/XML_RPC_Testserveur</url-pattern>
> >    </servlet-mapping>
> ></web-app>
> >
> >code is as follows:
> >
> >public class XML_RPC_Servlet extends HttpServlet{
> >
> >
> >
> >        protected void doGet(HttpServletRequest req,
> >                             HttpServletResponse res)
> >                  throws ServletException, IOException
> >       {
> >         res.setContentType("text/html");
> >         PrintWriter out = res.getWriter();
> >         out.println("<HTML><HEAD><TITLE>Hello There!</TITLE>"+
> >                     "</HEAD><BODY>Hello There!</BODY></HTML>");
> >         out.close();
> >       }
> >
> >    public String getServletInfo()
> >       {
> >         return "HelloClientServlet 1.0 by Stefan Zeiger";
> >       }
> >    }
> >
> >What i did:
> >-Started Tomcat (is configured to localhost:8080)
> >-opened Browser
> >-typed http://localhost:8080/XML_RPC_Testserveur
> >
> >- got only a message that the resource is unavailable (in french):
> >
> >*****************************
> >type Rapport d'�tat
> >message /XML_RPC_Testserveur
> >description La ressource demand�e (/XML_RPC_Testserveur) n'est pas
> >disponible.
> >******************************
> >
> >I am searching for a reason of this for nearly a day.
> >Is there anyone who can help me?
> >
> >Thanx Christian
> >
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