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http://nagoya.apache.org/bugzilla/show_bug.cgi?id=13969 ':' in parameter breaks encodeURL() and encodeRedirectURL() [EMAIL PROTECTED] changed: What |Removed |Added ---------------------------------------------------------------------------- Status|NEW |RESOLVED Resolution| |INVALID ------- Additional Comments From [EMAIL PROTECTED] 2002-11-18 16:43 ------- ':' and '%' are reserved characters in the URL spec (http://www.w3.org/Addressing/rfc1738.txt, see section 5). You need to URL encoded them, or you'll get either a MalformedURLException or undefined behaviour. It seems probably you've misunderstood the meaning of encodeURL(). This doesn't URL-encode a string (yes it does sound similar :) ) It adds the session id if you're using URL rewriting to maintain sessions. See http://jakarta.apache.org/tomcat/tomcat-4.0-doc/servletapi/javax/servlet/http/HttpServletResponse.html#encodeURL(java.lang.String) The correct way to write your code would be: <% response.sendRedirect(response.encodeRedirectURL("bug.jsp?ready="+java.net.URLEncoder.encode("Saturday 04:30"))); %> this is JDK 1.3, in JDK 1.4, URLEncoder.encode(String) is deprecated and you need to specify the charset for encoding: <% response.sendRedirect(response.encodeRedirectURL("bug.jsp?ready="+java.net.URLEncoder.encode("Saturday 04:30","UTF8"))); %> -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>
