On 2014-03-07 12:03, Balazs Kezes wrote:
> When you enumerate all the background colors via 'for i in {0..255} ;
> do printf "\x1b[38;5;${i}mcolour${i}\n"; done'
Sorry, that should say this (s/38/48/g):
When you enumerate all the background colors via 'for i in {0..255} ; do
printf "\x1b[48;5;${i}mcolour${i}\n"; done'
--
Balazs
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