Raul Raja Martinez,
That worked... Thanks.
The Hibernate SQL I wrote did not. I modified it some but that is not going so
well.
Unable to resolve expression 'userName' for [EMAIL PROTECTED]
binding: ExpressionBinding[Login userName]
location: context:/Login.html, line 18
ognl.OgnlException
userName
java.lang.NullPointerException
Stack Trace:
*
com.entercite.finance.model.abstrt.LoginComponent.getUserName(LoginComponent.java:25)
* sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
* sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
* sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
Turning on the SQL output I also get this:
Hibernate: select login0_.id as id, login0_.user_id as user2_0_,
login0_.user_name as user3_0_, login0_.password as pass
word0_, login0_.permission_type as permission5_0_, login0_.insert_date as
insert6_0_, login0_.modify_date as modify7_0_
from login login0_ where login0_.user_name=? and login0_.password=?
protected Object find(Class clazz, String value1, String value2){
Object obj = null;
try {
startOperation();
Query query = session.createQuery(
"from " + clazz.getName() +
" where userName = ? and password = ?");
query.setParameter(0, value1, Hibernate.STRING);
query.setParameter(1, value2, Hibernate.STRING);
obj = query.uniqueResult();
tx.commit();
} catch (HibernateException e) {
handleException(e);
} finally {
HibernateFactory.close(session);
}
return obj;
}
Do I have to write the SQL more like this example:
Query q = s.createQuery("from foo in class Foo where foo.name=:name and
foo.size=:size");
q.setProperties(fooBean); // fooBean has getName() and getSize()
List foos = q.list();
--
___________________________________________________
Play 100s of games for FREE! http://games.mail.com/
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
