Thanks for clarifying.
On Sun, 26 Feb 2023, 18:48 Oscar Benjamin, <oscar.j.benja...@gmail.com>
wrote:
> On Sun, 26 Feb 2023 at 11:33, Suchit K <suchitkarunaka...@gmail.com>
> wrote:
> >
> > Why does Poly.integrate() function doesn't give correct answer for
> asymptotic expressions like O(x**2)?
> > Example:
> > from sympy import *
> > x = Symbol('x')
> > exp = Poly(O(x**4))
> > print(exp.integrate()) #prints 1/2*O(x**4)**2 instead of O(x**5)
>
> A Poly object considers itself to be a polynomial function of some
> generator so Poly(O(x**4)) is a polynomial function of O(x**4). Notice
> that when you call integrate here you don't specify what variable you
> want to integrate with respect to but if you had specified
> exp.integrate(x) you would have seen an error because the Poly
> considers itself to be a function of O(x**4) rather than x.
>
> There is no way that Poly can do anything sensible with something
> O(x**4) so just don't use Poly for this:
>
> >>> O(x**4).integrate(x)
> O(x**5)
>
> Calculus with big-O objects is still questionable but SymPy currently
> has the behaviour you expect for integration and differentiation.
>
> --
> Oscar
>
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