That is precisely what I was looking for.
On Tuesday, April 19, 2022 at 3:24:00 PM UTC+1 gu...@uwosh.edu wrote:
> Alternative path that works better with complicated derivatives. Also
> shows the nicer output inside Jupyter notebooks.
> [image: Screen Shot 2022-04-19 at 9.23.21 AM.png]
>
> On Tuesday, April 19, 2022 at 8:16:25 AM UTC-5 gu...@uwosh.edu wrote:
>
>> Is this the behavior you are trying to get?
>>
>>
>> >>> from algebra_with_sympy import *
>> >>> algwsym_config.output.human_text=True
>> >>> var('psi k x')
>> (psi, k, x)
>> >>> eq1=Eqn(psi, exp(I*k*x))
>> >>> eq1
>> psi = exp(I*k*x)
>> >>> eq2 =diff(eq1,x)
>> >>> eq2
>> Derivative(psi, x) = I*k*exp(I*k*x)
>> >>> eq2.subs({exp(I*k*x):psi})
>> Derivative(psi, x) = I*k*psi
>>
>> Jonathan
>> On Tuesday, April 19, 2022 at 7:50:54 AM UTC-5 andre...@gmail.com wrote:
>>
>>> When I differentiate the function
>>>
>>> ψ = exp(I*(k*x))
>>>
>>> I get
>>>
>>> i*k*exp(I*(k*x)). [which is i*k*ψ]
>>>
>>> Is there a way to get exp(I*(k*x)) substituted with ψ, in order to get
>>> the shorter expression i*k*ψ ?
>>>
>>> Thanks,
>>> André
>>>
>>>
>>>
>>>
>>>
>>>
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