A cppcode would be useful to have for things like this (or just a flag
to ccode if the differences are minor).

Aaron Meurer

On Fri, May 13, 2016 at 4:17 PM, Jason Moore <[email protected]> wrote:
> You can subclass the CCodePrinter and change the method for sympy.I to print
> as you like. Examples are here:
> http://docs.sympy.org/latest/modules/printing.html
>
>
> Jason
> moorepants.info
> +01 530-601-9791
>
> On Thu, May 12, 2016 at 8:01 PM, chaowen guo <[email protected]> wrote:
>>
>> Hi:
>>
>> The output of sympy.ccode(1+sympy.I) is '1+I'
>>
>> However, in c++14 mode, like g++ -std=c++14 source.cpp, the g++ compiler
>> does not think I is the imaginary unit.
>>
>> But in the http://en.cppreference.com/w/cpp/numeric/complex, I know that
>> after
>>
>> using namespace std::complex_literals;
>> I can use 1i to represent the imaginary unit.
>>
>> So how to tell ccode not to convert sympy.I into I but 1i?
>>
>> I just know that there just exists ccode to convert sympy expression into
>> c code. But I can not find any cppcode to convert sympy expression into c++
>> code.
>>
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