On Tuesday, May 13, 2014 8:02:22 PM UTC+2, Abhishek K Das wrote:
>
> It requires an Interval as the third input parameter , what you are
> passing is basically a tuple of two numbers . If you write it as
> Interval(0,oo) instead of (0.oo) .
> It works fine !
>
>
In [4]: X = ContinuousRV(x, exp(-x), Interval(0, oo))
In [5]: P(X < Rational(1,2))
Out[5]:
-1/2
- ℯ + 1
In [15]: integrate(exp(-x), (x, 0, P(X < Rational(1,2))))
Out[15]:
-1/2
-1 + ℯ
- ℯ + 1
Is that the right answer? I thought it would be log(2)
In [18]: integrate(exp(-x), (x, 0, log(2)))
Out[18]: 1/2
I mean, the area below the probability function from 0 to log(2) is 1/2.
Right?
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