> On Nov 1, 2015, at 20:15, Adrian Chadd <adrian.ch...@gmail.com> wrote:
> 
> well, there's one cpu, nbuf=128, so lofreebuffers will be
> MIN(nbuf/25+20, 128); nbuf=128, so it'll be 25.
> hifreebuffers will be .. (3*25)/2, so 37.

The values calculated via the old formulas were 12 and 24, BTW. What’s your 
maxbufspace set to?
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