On Thu, 2020-06-11 at 16:29 +0200, Steffen Nurpmeso wrote:
> Hello.
> 
> Mateusz Piotrowski wrote in
> <995726df-cb28-c294-09ca-6cca302b2...@freebsd.org>:
>  |On 6/11/20 12:06 AM, Steffen Nurpmeso wrote:
>  |> Yuri Pankov wrote in
>  |> <a5e45631-bf32-56bc-4c03-0d0ad1d10...@yuripv.dev>:
>  |>|Mateusz Piotrowski wrote:
>  |>|> Author: 0mp (doc,ports committer)
>  |>|> Date: Wed Jun 10 19:23:58 2020
>  |>|> New Revision: 362017
>  |>|> URL: https://svnweb.freebsd.org/changeset/base/362017
>  |>|> 
>  |>|> Log:
>  |>|>    Read commands from stdin when -f - is passed to sed(1)
>  |>  ..
>  |>|Am I reading it wrong, or is it the same test case added 3 times?
>  |>
>  |> It also used "Fl f Cm -" instead of "Fl f Ar -".  Just saying..
> 
>  |Which is correct. "-" is not a variable here. It is a fixed string hence
>  |the use of Cm.
> 
> I would rather say no, .Ar is an argument (to the ".Fl"ag f),
> whereas .Cm is a command modifier:
> 
>    Command Modifiers
>      The command modifier is identical to the '.Fl' (flag) command with the
>      exception that the '.Cm' macro does not assert a dash in front of every
>      argument.  Traditionally flags are marked by the preceding dash, however,
>      some commands or subsets of commands do not use them.  Command modifiers
>      may also be specified in conjunction with interactive commands such as
>      editor commands.
> 

Yeah, but...

   The '.Fl' macro without any arguments results in a dash representing
   stdin/stdout. Note that giving '.Fl' a single dash will result in
   two dashes. The '.Fl' macro is parsed and is callable.

And that seems to argue that "Fl f Fl" is correct.

-- Ian


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