Hans Petter Selasky wrote:
On 09/24/17 01:46, Stephen Hurd wrote:
Basically, it changed from this:
foreach (mbuf in rx) {
if (lro && tcp_lro_rx(mbuf) == 0)
continue;
if_input(mbuf)
}
To this:
prev_mbuf = first_mbuf = NULL;
foreach (mbuf in rx) {
if (lro && tcp_lro_rx(mbuf) == 0)
continue;
if (prev_mbuf) {
prev_mbuf->m_nextpkt = mbuf;
prev_mbuf = mbuf;
}
else {
first_mbuf = prev_mbuf = mbuf;
}
}
if (first_mbuf)
if_input(first_mbuf);
So while before it called if_input() for each separate mbuf that was
not LROed, it now builds a chain of mbufs that were not LROed, and
makes a single call to if_input() with the whole chain. For cases
like packet forwarding where no packets are LROed, performance is
better.
Can such a similar logic be applied inside TCP LRO aswell?
It looks like it would be more complex to do a similar thing in
tcp_lro.c, and I'm not certain it would help much except in cases with a
large number of streams that mostly end up not being coalesced. Taking
a quick look, tcp_lro_flush() would need to be modified to return an
mbuf head and tail, then the caller would need to be responsible for
combining them into a single mbuf chain and calling if_input().
Either that, or an mbuf tail could be passed into tcp_lro_flush(), the
tail modified in there, and an mbuf head returned... that way it would
work something like this:
The caller would be something like this:
m_head = m_tail = NULL;
LIST_FOREACH(le, bucket, hash_next) {
head = tcp_lro_flush(lc, le, &m_tail);
if (m_head == NULL)
m_head = head;
}
if (m_head)
if_input(m_head);
And tcp_lro_flush() would be something like this:
struct mbuf *tcp_lro_flush(struct lro_ctrl *lc, struct lro_entry *le,
struct mbuf **tail)
{
...
if (*tail)
*tail->m_next = le->m_head;
*tail = le->m_tail;
...
return le->m_head;
}
Hrm, maybe it wouldn't be all that difficult after all. :-)
I'll be driving across the country later this week, so I don't want to
start poking into LRO then disappear, so if nobody else tries it out
before then, I should take a look in a couple weeks.
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