When a block is terminated, that block and all of its child blocks are 
terminated.  So if you terminate a black that has a held child block, the 
terminate should override the held block and terminate the entire block 
that you asked to be terminated.  Note that the STAX Monitor simply 
submits HOLD, TERMINATE, RELEASE, etc requests to the STAX service, so its 
the STAX service, not the STAX Monitor that handles holding, terminating, 
and releasing blocks.  The STAX Monitor simply gets messages (via the 
Event service) to update it on what actions have taken place in the job).

The following STAX job demonstrates this.  If you run this job, it will 
hold Block2.  If you terminate Block1 (Block2's parent) or Block2 without 
first releasing Block2, then  message "After hold in Block2.  Should not 
be logged if Block1 or Block2 is terminated before Block2 is released" 
will not be logged and the job will then run Block 3.  This is working as 
designed.  Post again if this did not answer your question.

<?xml version="1.0" encoding="UTF-8" standalone="no"?> 
<!DOCTYPE stax SYSTEM "stax.dtd"> 
<stax> 

<defaultcall function="StartHere"/> 

<script> 
  machine = 'local' 
</script> 
 
<function name="StartHere"> 
  <sequence> 

    <block name="'Block1'">
      <sequence>

        <block name="'Block2'">
          <sequence>

            <log message="1">
              'In Block2 before hold'
            </log>
 
            <hold/>

            <log message="1">
              'After hold in Block2.  Should not be logged if Block1 or 
Block2 is terminated before Block2 is released'
            </log>

          </sequence>
        </block>
 
      </sequence>
    </block>
 
    <block name="'Block3'">
      <sequence>

        <log message="1">
          'Logged by Block3 which is run after Block2 completes'
        </log>

        <stafcmd name="'Delay for 5 seconds'">
          <location>'local'</location>
          <service>'DELAY'</service>
          <request>'DELAY 5s'</request>
        </stafcmd>

      </sequence>
    </block>

  </sequence> 
</function> 
</stax> 

--------------------------------------------------------------
Sharon Lucas
IBM Austin,   luc...@us.ibm.com
(512) 286-7313 or Tieline 363-7313




Strösser, Bodo <bodo.stroes...@ts.fujitsu.com> 
06/26/2009 11:53 AM

To
"'staf-users@lists.sourceforge.net'" <staf-users@lists.sourceforge.net>
cc

Subject
[staf-users] Wrong picture on STAXMon when terminating a block






Hi,
 
i'm using STAX 3.3.6
 
I think, there is a bug in STAXMon, that can be reproduced performing the 
following
steps:
 
- A STAX job holds the innermost block of itself using <hold/>.
- Now we kill a parent block, as we want some part of the job to be 
skipped when
  the block in "hold" is released.
- As soon as the parent block is terminated from STAXMon, STAXMon no 
longer
  displays the terminated block's childs, which I think is wrong.
- As the block in "hold" no longer is displayed, it can not be released 
via STAXMon.
 
When the Monitor window is closed and started again, the missing blocks 
are back.
 
Best Regards
Bodo
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