$(tu{uri.uparam,cic}) gets ERROR wrong format,
$(tu{uri.uparam}) return : phone
So, uparam return the value of parameter "user" .
I solved a problem by usage $(tu{param.value,cic,;})
BR
Julia
On Tue, Sep 30, 2014 at 12:09 PM, Daniel-Constantin Mierla <
mico...@gmail.com> wrote:
> Hello,
>
>
> On 30/09/14 10:41, Julia Boudniatsky wrote:
>
> Hello,
>
> Some Uri transformations stopped working after upgrade from 3.3 to 4.1.6.
>
>
>
> *To: <sip:01412127775678;cic=012;csel=noind@10.25.153.150:5060
> <http://noind@10.25.153.150:5060>;user=phone>*
>
>
>
> *In v3.3*
>
>
>
> $tu({uri.params}) return: cic=012;csel=noind
>
> $tu({uri.param,cic}) return: 012
>
>
>
> *In v4.1.6*
>
>
>
> $tu({uri.params}) return : user=phone
>
> $tu({uri.param,cic}) return :
>
>
> looks like this is happening as a fix, as the cic is an username
> parameter, not a uri parameter.
>
> You should use {uri.uparam,cic}:
>
> http://www.kamailio.org/wiki/cookbooks/devel/transformations#uriuparam
>
> Cheers,
> Daniel
>
> --
> Daniel-Constantin Mierlahttp://twitter.com/#!/miconda -
> http://www.linkedin.com/in/miconda
>
>
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