Hi
Thanks, what I actually need is keep numbers and * and # and remove the
rest, something like
$rU = $(rU{re.subst,/![0-9*#]//g});
But I am not sure that ! works for negation.
Regards
On Mon, Feb 11, 2013 at 5:43 PM, Daniel Tryba <dan...@pocos.nl> wrote:
> On Monday 11 February 2013 11:24:36 Ali Jawad wrote:
> > I am using the below to strip "-" from destination numbers, it does work
> > just fine "I replace - with nothing", what i need to do now is to strip
> all
> > characters except 0-9 * and #. Is there anyway to do it using the
> following
> > configuration part
>
> You are using regular expression substitution, so yes this can be done:
> /[^0-9*#]//g
>
> Take a look at http://en.wikipedia.org/wiki/Regular_expression
> for more info.
>
*
*
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