Hello,
On 6/6/11 10:25 AM, Iñaki Baz Castillo wrote:
Hi, I wonder how feasible is the folowing:
I have a regular expresion like:
REGEXP = "^((1|20)|(13|3|4)|(5|6))"
There are 3 matching groups:
1) (1|20)
2) (13|3|4)
3) (5|6)
I want to match the RURI user, let's suppose $rU = "138787686223". In
this case the above regexp matches groups 1 and 2, but since group 2
matching is longest ("13" is longest than "1") I want to get value 2.
In case $rU = "999999" I need to get "null", in case $rU =
"1000022323" I need to get "1".
AFAIK there is no way to do it with current regular expression utils
in Kamailio, but maybe I miss something. Thanks a lot.
one option that comes in my mind is to break it in several if
conditions, matching one group at a time, written in the order of
preferences.
Cheers,
Daniel
--
Daniel-Constantin Mierla -- http://www.asipto.com
http://linkedin.com/in/miconda -- http://twitter.com/miconda
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