Thats too bad, but thanks for the clarification. 

Would this be possible if I wrote a custom extension for it? It should do 
the following:


   1. Detect if the docstring belongs to a class that inherits from 
ExternalPackageClass. 
   If yes, proceed with step 2. Otherwise continue normally
   2. Check if it is the docstring of the __call__ method. If yes, copy the 
   docstring from forward and use it.
   
   
Am Donnerstag, 4. Juni 2020 15:48:15 UTC+2 schrieb Komiya Takeshi:
>
> Hi, 
>
> The autodoc extension scans the target module and generates 
> documentation. No way to imitate it. As a workaround, you can insert 
> your content manually: 
>
> .. autoclass:: yourmodule.MyClass 
>
>     .. py:method:: __call__ 
>
>       Prints the input. 
>       This text is added to the document. 
>
>       Note: You should not use `:member:` option to the `autoclass` or 
> `automodule` directives. 
>       Then they'll create a document for MyClass.forward() automatically. 
>
>
> Thanks, 
> Takeshi KOMIYA 
>
> 2020年6月4日(木) 17:02 'CaptFugu' via sphinx-users <[email protected] 
> <javascript:>>: 
> > 
> > Suppose I have the following setup: 
> > 
> > class ExternalPackageClass: 
> >     def __call__(self, *args, **kwargs): 
> >         return self.forward(*args, **kwargs) 
> > 
> >     def forward(self, *args, **kwargs): 
> >         raise NotImplementedError 
> > 
> > 
> > class MyClass(ExternalPackageClass): 
> >     def forward(self, input): 
> >         r"""Prints the input""" 
> >         print(input) 
> > 
> > Can I configure autodoc somehow to document the forward() method as 
> __call__()? Otherwise I always need to include the information somewhere 
> that forward() is invoked if MyClass is called. 
> > 
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>  
>
>

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