from the spamd documentation:
"-m number, --max-children=number
Specify a maximum number of children to spawn. Spamd will wait until
another child finishes before forking again. Meanwhile, incoming connections
will be queued.
Please note that there is a OS specific maximum of connections that can
be queued (Try perl -MSocket -e'print SOMAXCONN' to find this maximum).
Also, this option causes spamd to create an extra pipe for each child."
1. use -m 10 instead of -m10 ;)
2. if you run 50 spamc's the first 10 connections will be served. The 40
others will be queued in this time till a spamc timeout occurs. If spamd has
finished one spamc request it will serve the next (of the 40 others).
/robert
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Tim B
Sent: Samstag, 3. Januar 2004 16:25
To: Spamassassin List
Subject: [SAtalk] spamd -m and a good number....
the spamd -m commandline option for max child processes... is that per
spamc call?
for instance if I use:
spamd -d -m10 -x -u filter
and I run 50 instances of spamc, does that mean that all 50 call of the
spamc process get 10 spamd child processes for a total of up to 500
spamd child processes?
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