Hello Bob,
Saturday, October 18, 2003, 9:04:18 AM, you responded to my query:
>> > spamassassin --lint
>> returns with no errors on the two 2.55 systems. However, starting with
>> the migration to 2.60 on the third system, lint with the same user_prefs
>> gives:
>> > Quantifier unexpected on zero-length expression before HERE mark in regex
>> > m/free\b?of\b?charge << HERE / at (no file), rule RM_bp_FreeOfCharge, line 1.
>> The rule which this applies to seems to be:
>> > body RM_bp_FreeOfCharge /free\b?of\b?charge/i
>> > describe RM_bp_FreeOfCharge Body mentions something free of charge
>> > score RM_bp_FreeOfCharge 0.10
BA> Do you mean /free\s?of\s?charge/i instead?
BA> /b is a word boundary; like ^ and $, it's a "zero-width assertion",
BA> looking for "a spot between two characters that has a "\w" on one
BA> side of it and a "\W" on the other side of it" (from `perldoc perlre`)
As a word boundary, would not \b also match . , / ?
My email client's regular expression help offers:
> Regular-Expression Assertions
> Assertion Matches Example Matches Doesn't Match
> ^ Start of string ^fool foolish Tomfoolery
> $ End of string fool$ April fool Foolish
> \b Word boundary be\bside be side Beside
> \B Nonword boundary be\Bside beside be side
I wouldn't have any problem with this documentation being wrong, but
from this documentation my understanding is that e\b?o should match
"e o", "e.o", "e-o", and "eo" (the latter if there is no word
boundary). Am I reading this wrong?
BA> '\b?' doesn't make sense with or without the '?' since 'e\bo' and 'f\bc'
BA> are always false (e,o,f,c are all matched by \w so you have \w on both
BA> sides of the \b...) Someone please correct me on this but it looks like
BA> this regex is equivalent to /freeofcharge/i -- it looks like lint is
BA> doing the right thing here.
BA> You probably want
BA> /free\s+of\s+charge/i
BA> or
BA> /free\s{0,10}of\s{0,10}charge/i (similar to /free\s*of\s*charge/i)
BA> The difference between /b and /s tripped me up for a long time because I
BA> kept thinking 'blank' not 'boundary' when I saw '/b'.
The problem is that I don't want just blanks, but want all other types
of word boundary conditions as well, periods, commas, dashes, etc.
Maybe if \b is wrong, then what I want is "/free\W?of\W?charge/i" or
"/free\W{0,10}of\W{0,10}charge/i" ???
Thanks.
Bob Menschel
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