Hi Hoss,
thanks for this answser, and is there a way to get the weight of a field ?
like that and use it in the bf? queryWeight
0.14232224 = (MATCH) weight(text:chien^0.2 in 9412049), product of:
0.0813888 = queryWeight(text:chien^0.2), product of:
0.2 = boost
6.5946517 = idf(docFreq=55585, numDocs=14951742)
0.061708186 = queryNorm
thanks
hossman wrote:
>
>
> : I don't get really, I try to boost a field according to another one but
> I've
> : a huge weight when I'm using qf boost like :
> :
> : /select?qt=dismax&fl=*&q="obama
> : meeting"&debugQuery=true&qf=title&bf=product(title,stat_views)
>
> bf is a boost function -- you are using a product fucntion to multiply the
> "title" field by the stat_views" field ... this doesn't make sense to me?
>
> i'm assuming the "title" field contains text (the rest of your score
> explanation confirms this). when you try to do a math function on a
> string based field it deals with the "ordinal" value -- the higher the
> string is lexigraphically compared to all other docs ,the higher the
> ordinal value.
>
> i have no idea what's in your stat_views field -- but i can't imagine any
> way in which multipling it by the ordinal value of your text field would
> make sense...
>
> : 5803675.5 = (MATCH)
> FunctionQuery(product(ord(title),sint(stat_views))),
> : product of:
> : 9.5142968E7 = product(ord(title)=1119329,sint(stat_views)=85)
> : 1.0 = boost
> : 0.06099952 = queryNorm
>
> : But this is not equilibrate between this boost in qf and bf, how can I
> do ?
>
> when it comes to function query, you're on your own to figure out an
> appropriate query boost to blanace the scores out -- when you use a
> product function the scores are going to get huge like this unless you
> balance it somehow (and that ord(title) is just making this massively
> worse)
>
>
> -Hoss
>
>
>
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