Scott:
It worked ok. Thanks a lot.
I use Tomcat and I would like to ask you another thing.
My Service dinamically invokes some other Services (as I told you :-) ),
so I get the URL of each of the Services dinamically (from my Database)
that I am going to call and send them some information.
The question is:
I want to test my application and, Is it possible tu run in the same
machine 2 Tomcats ?
If it is possible I could invoke each of those services just changing the
URL.
For example: I invoked the Listener over SOAP but this service is using
the same URL as my Service:
http://localhost:8080/soap/servlet/rpcrouter
Can I deploy another instance of Tomcat at the same time using a
different port number ?
for example: http://localhost:8010/soap/servlet/rpcrouter
Where Should I do ? Where Do I set the port number up ?
Thank you very much !!!
Max
On Mon, 2 Feb 2004 10:32:22 -0500, "Scott Nichol"
<[EMAIL PROTECTED]> said:
> How have you deployed Apache SOAP in your J2EE container? Is it a
> webapp? It should be. With Tomcat, for example, you would probably have
> a directory
>
> $CATALINA_HOME/webapps/soap
>
> for the webapp. All of the Apache SOAP classes would be in
>
> $CATALINA_HOME/webapps/soap/WEB-INF/classes
>
> Your service code should be deployed to that same directory (and its
> sub-directories to match your package declarations). In your case,
> because you use Apache SOAP classes in your service, this is your only
> deployment option (on Tomcat, at least; I don't think you have ever said
> which container you are using). For services that do not use Apache SOAP
> classes, another option (although definitely *not* recommended) is to put
> the service classes in $CATALINA_HOME/shared/classes.
>
> Scott Nichol
>
> Do not send e-mail directly to this e-mail address,
> because it is filtered to accept only mail from
> specific mail lists.
> ----- Original Message -----
> From: "Maximiliano Barone" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Saturday, January 31, 2004 4:30 PM
> Subject: Re: Server-Side as a Client of other Web Service
>
>
> Scott:
>
> Thank you very much for your answers.
> When my service dinamically tries to send the request (invoking) to other
> Web Services, it fails because it doesn´t find none of the following
> classes:
>
> - Constants
> - Parameter
> - Fault
> - Call
> - Response
>
> All of these classes belongs to org.apache.soap.rpc.*
> When I compile this in my IDE Java it works well, but when it is running
> in the Apache SOAP Server context (Server Side) it fails.
> I read the article that you told me about the classloaders, but what
> classes should I put in one of those directories ?
>
> Thanks.
>
> Max
>
>
> On Fri, 30 Jan 2004 11:25:59 -0500, "Scott Nichol"
> <[EMAIL PROTECTED]> said:
> > > 3) Could you please tell me how I can put the classes in the class loader
> > > of the server ?
> >
> > Since you are making the Call from code that is running in the context of
> > an Apache SOAP service, the classes *should* be available, and the
> > instantiation of Call should work.
> >
> > The exact set of classes available through class loaders depends on the
> > J2EE container you are using. With Tomcat, for example, the class
> > loaders are documented (for version 4.1) at
> > http://jakarta.apache.org/tomcat/tomcat-4.1-doc/class-loader-howto.html.
> >
> > For Apache SOAP services deployed in Tomcat, the classes are under the
> > WEB-INF/classes directory for the soap webapp. If that webapp was
> > deployed the "simplest" way, the full path to the classes is
> > $CATALINA_HOME/webapps/soap/WEB-INF/classes.
> >
> > > I will explain you this interaction:
> > >
> > > 1) A client sends some info (over Apache SOAP) to my Service. (OK)
> > > 2) My Service receives this call and saves the data internally. (OK)
> > > 3) My Service builds a new DOM Element and sends it to other services.
> > > (ERROR !)
> > >
> > > I can't see the ERROR of this third step because the Client (step 1) uses
> > > a servlet to invoke my
> > > Service and it internally invokes the other services. I know that my code
> > > is not working well because I comment that line of the
> > > new Call ("Call call = new Call();") and it works (without calling the
> > > services, of course).
> > > How can I see that error ?
> >
> > If your service code does nothing to trap an exception, an exception
> > thrown in the instantiation of Call will trace back on the stack into
> > Apache SOAP code (within RPCRouterServlet, I believe) that will catch it
> > and package it into a SOAP Fault that is returned to the client. A
> > common client coding practice is to check for a Fault and display its
> > contents, which would have the info.
> >
> > Further, the J2EE container will sometimes log Java exceptions, depending
> > on the container and possibly the configuration of the container.
> >
> > Scott Nichol
> >
> > Do not send e-mail directly to this e-mail address,
> > because it is filtered to accept only mail from
> > specific mail lists.
> > >
> > > Thanks
> > >
> > > Maxi
> > >
> > >
> > >
> > >
> > > On Fri, 30 Jan 2004 10:04:59 -0500, "Scott Nichol"
> > > <[EMAIL PROTECTED]> said:
> > > > Max: I am sending this directly to you as well as the list because my
> > > > e-mails to the list are not showing up.
> > > >
> > > > I have a number of comments.
> > > >
> > > > 1. You do not need to register anything to [de-]serialize a Vector. In
> > > > fact, the BeanSerializer may do things you do not want it to do.
> > > >
> > > > 2. Constants.NS_URI_LITERAL_XML is *not* the same as WSDL
> > > > document/literal. It is a custom encoding supported by Apache SOAP. It
> > > > will not allow you to use BeanSerializer, etc. It only works with
> > > > parameters that are DOM Element.
> > > >
> > > > 3. What error do you get when you try to instantiate a Call? You should
> > > > be able to do this if you have the classes available in a class loader
> > > > available to the server.
> > > >
> > > > Scott Nichol
> > > >
> > > > Do not send e-mail directly to this e-mail address,
> > > > because it is filtered to accept only mail from
> > > > specific mail lists.
> > > > ----- Original Message -----
> > > > From: "Maximiliano Barone" <[EMAIL PROTECTED]>
> > > > To: <[EMAIL PROTECTED]>
> > > > Sent: Friday, January 30, 2004 9:51 AM
> > > > Subject: Server-Side as a Client of other Web Service
> > > >
> > > >
> > > > > Hi ! I am developing a Service that receives a call from a Client over
> > > > > Apache SOAP like this:
> > > > >
> > > > > CLIENT:
> > > > >
> > > > > // Mapping registry
> > > > > SOAPMappingRegistry smr = new
> > > > > SOAPMappingRegistry();
> > > > > BeanSerializer beanSer = new BeanSerializer ();
> > > > >
> > > > > smr.mapTypes(Constants.NS_URI_SOAP_ENC, new QName("urn:UpdateUsrWS",
> > > > > "UpdateUsr"), Vector.class, beanSer, beanSer);
> > > > >
> > > > > // Build the call.
> > > > > Call call = new Call();
> > > > > call.setTargetObjectURI("urn:UpdateUsrWS");
> > > > > call.setMethodName("main");
> > > > > call.setEncodingStyleURI(Constants.NS_URI_LITERAL_XML);
> > > > >
> > > > >
> > > > > The Server Side (MyService: UpdateUsrWS) receives some information from
> > > > > the Client and invokes other Services over Apache SOAP too, so my Service
> > > > > (Server-Side) acts as a client too.
> > > > > The problem is that I am trying to create a new Call from my class and it
> > > > > doesn't work.
> > > > >
> > > > >
> > > > > SERVER (As a Client of other Web Services)
> > > > >
> > > > > Call call = new Call();
> > > > >
> > > > > Do you know if the SOAP Server supports this ?
> > > > > Any suggestion ?
> > > > >
> > > > > Thank you.
> > > > >
> > > > > Max
> > > > >
> > > > >
> > > > >
> > > > > --
> > > > > http://www.fastmail.fm - Sent 0.000002 seconds ago
> > > > >
> > >
> > > --
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> > >
>
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