Hi All, I want to know how can i access a request that has been sent thru the message.sent() method ..
for example.. i send my xml document through this soap method msg.send (new URL ("http://localserver/soap/messagerouter"), "urn:testservice", msgEnv); where msgEnv parsed is a soap xml. which contains the following xml file <?xml version="1.0" encoding="UTF-8" ?> <s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"> <s:Body> <name> <first> XXX </first > <last> YYY </last> </name> </s:Body> </s:Envelope> 1) now i need to parse the soap/xml document in the mentod called doRegister() deployed in urn:testservice. 2) here is am sample of the method doRegister public void doRegistration(Envelope env, SOAPContext req, SOAPContext res) throws IOException, MessagingException { try{ String firstName = null; String lastName = null; String output =null; Vector lovcEntries = env.getEnvelopeEntries(); //trying to get the xml file contents } catch(Exception ex){ System.out.println("Exception in the RegisterService :: doRegistration()"); } } i want to get the first and last name tag's from the SOAP/xml. how do i get it. but by using the above env.getEnvelopeEntries() i am not able to get entries. Can anyone suggest me how to parse the Sent xnl fine. can anyone help me pls.... Thanks, Kavitha -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>