I'm not sure there is a command to do this is one go. But... This command will list all nodes, one per line. sinfo -Nl -p <queue-name>
This command will list all the jobs associated with a given node: squeue -w <node-name> Adding the "-P" switch puts it in "parsable" mode. We've just written several python scripts to wrap around some commands to give us formats that we want. > On Apr 27, 2017, at 16:19, Mark London <[email protected]> wrote: > > > Hi - I want a method to create a list all the cluster nodes, with one node > line per line, and include the job(s) running, for each node. I haven't > quite found a command that will do this. Before I write a script to do > this, I was wondering if someone else has already done this. Or whether > there is a command to do it, that I'm not aware of. Thanks very much. > > Mark London
