I would just say, for clarity, that  the "input" of the regulator
should be connected to the power supply positive and the "ground" of the
regulator should be connected to the silver anode of the cell.  The
selected current control resistor should be from the "ground" terminal
to the "output" terminal of the regulator.  The drawing on page 22 is a
bit confusing, you shouldn't need to use the two capacitors, and the
silver cell is in place of "RL" (Resistive Load).

Dan

-----Original Message-----
From: Marshall Dudley [mailto:[email protected]] 
Sent: Monday, October 16, 2006 11:13 AM
To: [email protected]
Subject: Re: CS>Diodes with 3 leads ( Question and Use )

I would not recommend using a constant current diode for that. I would
use the method I am using on my CS to make the current 80 mA.  Take a
7805 5 volt regulator and connect a resistor between the output and the
control leads.
Then connect the anode of the regulator to the positive supply, and the
gate to the silver anode of the CS maker (or whatever you are wanting to
supply positive current for).

The resistor can be computed as 5V/i, so for a 20 mA current you need to
use a resistor of 250 ohms (240 or 270 would probably be close enough).

This cannot be used for low currents, like 1 mA since the device itself
will shunt about .5 mA for it's own internal operation. But for currents
over 10 mA it works great, and is solid as a rock, hardly varying with
voltages of between 4 and 40 across it.

This configuration is shown on page 22 of
http://www.ee.washington.edu/stores/DataSheets/voltreg/7805.pdf

Marshall


"M. G. Devour" wrote:

> So, to drag the discussion a little OT, is there an easy tutorial or 
> design article about this FET current regulator somewhere? How do you 
> set the current level?
>
> I need to prototype a 20/40/80 etc.... ma regulator to drive some 
> LED's for another project. :)
>
> Mike D.
>


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