Re: [Wireshark-users] Average MBit/sec

2008-02-26 Thread Stephen Fisher
On Tue, Feb 26, 2008 at 09:59:10PM -0800, Jehanzeb Khan wrote: > Stephen i think you meant to say 'divide' by 8 to go from MBit/Sec to > MB[yte]/sec :) You're right, thanks for catching that. I wasn't thinking when I posted that. Steve ___ Wiresh

Re: [Wireshark-users] Average MBit/sec

2008-02-26 Thread ronnie sahlberg
unless you use >=1GbE or FC physical layers where there are 10 bits per byte in the physical transport. (but we never see the real physical layer in wireshark anyway) On Wed, Feb 27, 2008 at 12:54 PM, Stephen Fisher <[EMAIL PROTECTED]> wrote: > On Tue, Feb 26, 2008 at 05:45:12PM -0800, Greg Reed

Re: [Wireshark-users] Average MBit/sec

2008-02-26 Thread Jehanzeb Khan
Stephen i think you meant to say 'divide' by 8 to go from MBit/Sec to MB[yte]/sec :) Regards Jehanzeb Khan Stephen Fisher <[EMAIL PROTECTED]> wrote: On Tue, Feb 26, 2008 at 05:45:12PM -0800, Greg Reed wrote: > For MB/sec would I move the decimal point 2 places to the right from > the

Re: [Wireshark-users] Average MBit/sec

2008-02-26 Thread Stephen Fisher
On Tue, Feb 26, 2008 at 05:45:12PM -0800, Greg Reed wrote: > For MB/sec would I move the decimal point 2 places to the right from > the output of MBit/sec? There are 8 bits in a byte, so you would actually multiply the MBit/sec by 8 to get MB[yte]/sec. Steve _

[Wireshark-users] Average MBit/sec

2008-02-26 Thread Greg Reed
Greetings- I am new to using Wireshark and was looking at the Average MBit/sec under the Summary pick of the Statistics tab. For MB/sec would I move the decimal point 2 places to the right from the output of MBit/sec? Thanks for the help, Greg __