My tables are:
t_contact (the parent)
t_paypal
t_paypal_fails
t_paypal_contacted
All the child tables refer to the parents ID.
I have a controller that looks like this:
@auth.requires_login()
def paypal_manage():
form =
SQLFORM.smartgrid(db.t_contact,linked_tables=['t_paypal','t_paypal_fail
Hi Villas
I like the idea of getting the ID from a var instead of args, however I am
still not sure how to go about getting the ID of the current record I am
viewing/editing in smartgrid.
Forgive my noobishness.
M
On Monday, 19 November 2012 08:57:09 UTC, villas wrote:
>
> If you cannot contr
Hi Villas
I like the idea of using a var instead of args but I am still uncertain of
how I get the ID of the current record I am viewing/editing in smartgrid.
Mike
On Monday, 19 November 2012 08:57:09 UTC, villas wrote:
>
> If you cannot control the order of args, you could still look for an
it using similar code to your link function but it
seems you can only request the id of the current record using
db.t_contact.id from within the parameters of your SQLFORM.smartgrid
request.
Its a dirty hack but it seems to work.
Mike
On Tuesday, 20 November 2012 07:15:22 UTC, Johann Spies
Hiya
This works a treat thanks.
Mike
On Thursday, 22 November 2012 14:32:38 UTC, Alan Etkin wrote:
>
> > On Thursday, November 22, 2012 9:07:23 AM UTC-3, Michael Hall wrote:I
> have the following code for my join in SQLFORM.grid:
>
> Perhaps you can pass something
I have a SQLFORM.grid with a join, however when I insert, edit or update a
record displayed in the grid I am only ever given a form for the parent
table.
What is the preferred method for creating insert, update and delete forms
for a joined SQLFORM.grid? Common sense tells me that it is the met
Just bumping this as I am still struggling with view and edit for joined
SQLFORM.grid's
On Wednesday, 28 November 2012 11:17:36 UTC, Michael Hall wrote:
>
> I have a SQLFORM.grid with a join, however when I insert, edit or update a
> record displayed in the grid I am only ever gi
I would like to have a smartgrid that references its parent table in
linked_tables, what is the web2py way of doing this? I have found some help
in this thread:
https://groups.google.com/forum/?fromgroups=#!topic/web2py/vDGJdct550Q but
the solution is a bit sketchy due to it modifying sqlhtml.p
/Field>('pass_mark',
'text'),
format = '%(name)s')
On Monday, 29 April 2013 13:32:10 UTC+1, Michael Hall wrote:
>
> I would like to have a smartgrid that references its parent table in
> linked_tables, what is the web2py way of doing this? I have found som
/www.web2py.com/examples/global/vars/Field>('pass_mark',
'text'),
format = '%(name)s')
On Monday, 29 April 2013 13:32:10 UTC+1, Michael Hall wrote:
>
> I would like to have a smartgrid that references its parent table in
> linked_tables, wh
Was there ever a fully working solution proposed or discovered for using
executesql with grid and smartgrid?
On Friday, 22 June 2012 07:54:05 UTC+1, pbreit wrote:
>
> I have an app where I pull down 5,000 records. I started with DAL and
> db.item.ALL and it was taking around 4 seconds. I added 5
Hiya
Is there a changelog for 2.6.3 I just updated this morning and had an issue
with an experimental virtual field for sqlform.smartgrid. I removed the
field and everything worked fine and the overall speed of the app has
improved. I am interested to know if you have removed this experimental
What worked for me when this happened was simply to download the latest
source of the site and unzip it to my web2py folder thus overwriting the
incomplete upgrade. I restart web2py or in the case of my webfaction server
I restart apache which restarts web2py and then everything works as normal
I am not the most awesome SQL person and as such I am having trouble
constructing a query I need.
I have two tables in a database called "old". The parent table is called
"members" and there is a child table called "courses".
#
old.define_table('members',
Field('id'),
Field('pro
Hey guys this works a treat and I have learned something new. Thanks for
the help.
On Tuesday, 24 September 2013 11:16:52 UTC+1, Michael Hall wrote:
>
> I am not the most awesome SQL person and as such I am having trouble
> constructing a query I need.
>
> I have two tables in a
If I have the following model:
db.define_table('user_images',
Field('my_image', 'upload',
label=T('My Image')),
)
and In my rendered html view I have a canvas, the canvas has produced an
image saved in the variable
document.getElementById('canvas').src = dataURL;
Underneath the i
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