I was so fixed in the string format, that I was ignoring the basic math!
=/
Thanks to everyone for the tips!!
This solve very well:
"%i.%02i" % divmod(348,100)
Em quinta-feira, 29 de novembro de 2012 09h12min39s UTC-2, Joe Barnhart
escreveu:
>
> Bzzzt! Thanks for playing!
>
> You get 3.0
Bzzzt! Thanks for playing!
You get 3.0 for your result. (I'm not a python genius but I keep an
interpreter handy just to type in stuff and see what I get.)
>>> round(int("348")/100,3)
3.0
In your example, you rounded the result AFTER the integer division of
348/100. But the result of
Il 29/11/12 10:49, Joe Barnhart ha scritto:
Hmmm...
That would give "3" since Python 2.x keeps the calculation as integer
(it won't coerce it to a float).
He could do a=int(a)/100.0 But that puts it into a floating point
value, and rounding sometimes gives surprising and unexpected results
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